#include <iostream>
#include <string>
using namespace std;
int main()
{
string s;
string str = "";
cin >> s;
char pre;
for(int i = 0; i < s.length(); i++) {
if(47 < s[i] and s[i] < 58){
while((s[i]-48) > 1) {
str += pre;
s[i]--;
}
}
if(96 < s[i] and s[i] < 123) {
str += s[i];
pre = s[i];
}
//cout << str << endl;
}
cout << str;
return 0;
}
On Wed, Jul 25, 2012 at 6:46 AM, Sathish babu <satbrucei...@gmail.com>wrote:
> can anyone provide the code to convert ab1cd3 to abcddd
> **~Sathish Babu~**
>
>
>
> On Tue, Jul 24, 2012 at 11:39 PM, Mind Boggler <min.b...@gmail.com> wrote:
>
>> Traditional decryption problem
>> Convert a3b2c5 into aaabbccccc
>> Can anyone Put forward an algo for the test case: a3b1c3d1
>> Thanx
>>
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>>
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--
With regards,
Manish kumar untwal
Indian Institute of Information Technology
Allahabad (2009-2013 batch)
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