^ : I guess this is the only in-place method.
It prevents the space from being printed.
does not 'remove' it though ; just replaces with a bell sound !
On Wed, Aug 1, 2012 at 11:12 PM, atul pandey <atulpande...@gmail.com> wrote:
> Geeks just look at this...correct me if i am wrong...!!
>
> int main()
> {
> char s[] = "how are you friends";
> int i=0;
> while(s[i] != '\0')
> {
> if(s[i] == ' ' && s[i+1]==' ')
> { s[i+1] = '\b'; i++; }
> else if(s[i]== ' ') s[i]='\a';
> i++;
> }
> printf("%s\n", s);
> }
>
> On Wed, Aug 1, 2012 at 5:01 PM, atul anand <atul.87fri...@gmail.com>wrote:
>
>> j=0;
>> for i to len
>> if(str[i] != ' ' )
>> {
>> str[j]=str[i];
>> j++;
>> }
>> end
>> str[j]='\0';
>>
>> On Wed, Aug 1, 2012 at 10:08 AM, Sambhavna Singh <coolsambha...@gmail.com
>> > wrote:
>>
>>> Please have a look at this :
>>> http://www.careercup.com/question?id=14433699&utm_source=feedburner&utm_medium=email&utm_campaign=Feed%3A+Careercup+%28CareerCup%29
>>>
>>> What does inplace shifting imply here? Cant i keep 2 pointers and
>>> overwrite a non space character onto a space character and advance both
>>> pointers till one again hits a space character and other a non-space
>>> character? Does that violate the condition given in the question?
>>>
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>
>
>
> --
> Thanks & Regards,
> * Atul Kumar Pandey*
>
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--
- - - - - - - - - - - -
With Regards
Daksh Talwar
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