@ above
small correction..
/*
By O(n^3), in this case it means O((N/K ^ K)) .....
*/
Therefore, N = 9, K=3.. hence (9/3)^3 = 27

On Aug 4, 4:24 am, Lucifer <sourabhd2...@gmail.com> wrote:
> @vikas
> I believe that if we generalize the question saying that there are N
> students and K schools, such that each school can accommodate at max
> (N/K) students (which means each school needs to accommodate exactly
> (N/K) students. Given this we need to find the minimum distance.
>
> By O(n^3), in this case it means O((N/K ^ 3)) .....
>
> Am I right ?
>
> On 1 Aug, 11:48, vikas rai <vikasloves...@gmail.com> wrote:
>
>
>
>
>
>
>
> > There is a set of 9 students and 3 schools Every school can be alloted
> > atmax 3 students .Every school and student has its coordinates .Now we have
> > to allot student in such a way that the sum of distance from all the
> > student to the school should be minimum.
> > We have to solve this in less than O(n^3) .

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