@vicky

Got it . thanks ..is it possible to ignore the preprocessing time when
calculating time complexity?


On Sun, Aug 12, 2012 at 10:02 PM, shady <sinv...@gmail.com> wrote:

> @venkat +1
>
> On Sun, Aug 12, 2012 at 9:09 PM, ~*~VICKY~*~ <venkat.jun...@gmail.com>wrote:
>
>> @Arun: This approach is constant time once the array is build for any
>> queries that follows. :) You know sum for all possible rectangles in the
>> given 2d array thats makes it better than computing sum for each input.
>> Hope it makes sense
>>
>>
>> On Sun, Aug 12, 2012 at 9:07 PM, ~*~VICKY~*~ <venkat.jun...@gmail.com>wrote:
>>
>>> Fine, the basic idea of using dp here is sum of each rectangle is a
>>> dependent sub problem. So when u find sum for smaller rectangle we can use
>>> it to compute sum of bigger rectangle with new coordinates added to
>>> previous small rectangle. So u can compute the sum array by using this
>>> formula
>>>
>>> sum[i][j] = sum[i-1][j-1] + (sum[i-1][j] - sum[i-1][j-1]) + (sum[i][j-1]
>>> - sum[i-1][j-1])+ip[i][j]
>>>                 [smaller rect]   [that row sum value]            [that
>>> col sum value]
>>>
>>>
>>>
>>> On Sun, Aug 12, 2012 at 8:54 PM, Srividhya Sampath <
>>> srisam261...@gmail.com> wrote:
>>>
>>>> @vicky
>>>>
>>>> can yo explain the logic behind the 'Sum Array' computation (if
>>>> possible elaborately )?
>>>>
>>>>
>>>> On Sun, Aug 12, 2012 at 8:19 PM, ~*~VICKY~*~ 
>>>> <venkat.jun...@gmail.com>wrote:
>>>>
>>>>> Lets build the array for the example you gave.
>>>>>
>>>>> i/p:
>>>>>
>>>>> 0 1 2 3
>>>>> 4 5  6 7
>>>>> 8 9 10 11
>>>>>
>>>>> (x1,y1) = (0,0)
>>>>> (x2,y2) = (1,2)
>>>>> sumArray
>>>>> 0  1     2    3
>>>>> 4  10  18   28
>>>>> 12 27  45  66
>>>>> (will take O(n^2) to build above array)
>>>>> So now when you get coordinates as input, you can calc the sum by
>>>>>
>>>>> Ans = sumArray[x2][y2] - sumArray[x1][y1] + ip[x1][y1]
>>>>>
>>>>> For our case it will be Ans = 18-0+0 = 18
>>>>>
>>>>> Please lemme know if any bugs with the logic.
>>>>>
>>>>>
>>>>> On Sun, Aug 12, 2012 at 6:27 PM, Srividhya Sampath <
>>>>> srisam261...@gmail.com> wrote:
>>>>>
>>>>>>
>>>>>> @ Vicky
>>>>>>
>>>>>> Can yo explain with an illustration ?
>>>>>>
>>>>>>
>>>>>> On Sat, Aug 11, 2012 at 10:07 PM, ~*~VICKY~*~ <
>>>>>> venkat.jun...@gmail.com> wrote:
>>>>>>
>>>>>>> May be you can consider creating a 2d array to pre process and store
>>>>>>> all the rectangle sums as a dependent subproblem, the sum of larger rect
>>>>>>> will be currValuesAdded+OldRectSum. So when you get the coordinate as 
>>>>>>> input
>>>>>>> u can calc the needed sum by subtracting sum of big rect and small rect
>>>>>>> which is not included in the given coordinates. This can be called 
>>>>>>> constant
>>>>>>> time if u don't include the preprocessing time.
>>>>>>>
>>>>>>>
>>>>>>> On Sat, Aug 11, 2012 at 9:57 PM, adarsh kumar <algog...@gmail.com>wrote:
>>>>>>>
>>>>>>>> Sum of the integers meaning? Do you mind giving an example test
>>>>>>>> case?
>>>>>>>>
>>>>>>>> regards.
>>>>>>>>
>>>>>>>> On Sat, Aug 11, 2012 at 7:10 PM, Srividhya 
>>>>>>>> <srisam261...@gmail.com>wrote:
>>>>>>>>
>>>>>>>>> hi all:)
>>>>>>>>>
>>>>>>>>> The coordinates of a rectangle will be specified. there is a
>>>>>>>>> matrix of integers. yo should find the sum of the integers that fall 
>>>>>>>>> in the
>>>>>>>>> region specified by the  coordinates .
>>>>>>>>>
>>>>>>>>> The solution to be in constant time .
>>>>>>>>>
>>>>>>>>> --
>>>>>>>>> You received this message because you are subscribed to the Google
>>>>>>>>> Groups "Algorithm Geeks" group.
>>>>>>>>> To view this discussion on the web visit
>>>>>>>>> https://groups.google.com/d/msg/algogeeks/-/qHSmXBshmS4J.
>>>>>>>>> To post to this group, send email to algogeeks@googlegroups.com.
>>>>>>>>> To unsubscribe from this group, send email to
>>>>>>>>> algogeeks+unsubscr...@googlegroups.com.
>>>>>>>>> For more options, visit this group at
>>>>>>>>> http://groups.google.com/group/algogeeks?hl=en.
>>>>>>>>>
>>>>>>>>
>>>>>>>>  --
>>>>>>>> You received this message because you are subscribed to the Google
>>>>>>>> Groups "Algorithm Geeks" group.
>>>>>>>> To post to this group, send email to algogeeks@googlegroups.com.
>>>>>>>> To unsubscribe from this group, send email to
>>>>>>>> algogeeks+unsubscr...@googlegroups.com.
>>>>>>>> For more options, visit this group at
>>>>>>>> http://groups.google.com/group/algogeeks?hl=en.
>>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>> --
>>>>>>> Cheers,
>>>>>>>
>>>>>>>   Vicky
>>>>>>>
>>>>>>>  --
>>>>>>> You received this message because you are subscribed to the Google
>>>>>>> Groups "Algorithm Geeks" group.
>>>>>>> To post to this group, send email to algogeeks@googlegroups.com.
>>>>>>> To unsubscribe from this group, send email to
>>>>>>> algogeeks+unsubscr...@googlegroups.com.
>>>>>>> For more options, visit this group at
>>>>>>> http://groups.google.com/group/algogeeks?hl=en.
>>>>>>>
>>>>>>
>>>>>>  --
>>>>>> You received this message because you are subscribed to the Google
>>>>>> Groups "Algorithm Geeks" group.
>>>>>> To post to this group, send email to algogeeks@googlegroups.com.
>>>>>> To unsubscribe from this group, send email to
>>>>>> algogeeks+unsubscr...@googlegroups.com.
>>>>>> For more options, visit this group at
>>>>>> http://groups.google.com/group/algogeeks?hl=en.
>>>>>>
>>>>>
>>>>>
>>>>>
>>>>> --
>>>>> Cheers,
>>>>>
>>>>>   Vicky
>>>>>
>>>>>  --
>>>>> You received this message because you are subscribed to the Google
>>>>> Groups "Algorithm Geeks" group.
>>>>> To post to this group, send email to algogeeks@googlegroups.com.
>>>>> To unsubscribe from this group, send email to
>>>>> algogeeks+unsubscr...@googlegroups.com.
>>>>> For more options, visit this group at
>>>>> http://groups.google.com/group/algogeeks?hl=en.
>>>>>
>>>>
>>>>  --
>>>> You received this message because you are subscribed to the Google
>>>> Groups "Algorithm Geeks" group.
>>>> To post to this group, send email to algogeeks@googlegroups.com.
>>>> To unsubscribe from this group, send email to
>>>> algogeeks+unsubscr...@googlegroups.com.
>>>> For more options, visit this group at
>>>> http://groups.google.com/group/algogeeks?hl=en.
>>>>
>>>
>>>
>>>
>>> --
>>> Cheers,
>>>
>>>   Vicky
>>>
>>>
>>
>>
>> --
>> Cheers,
>>
>>   Vicky
>>
>>  --
>> You received this message because you are subscribed to the Google Groups
>> "Algorithm Geeks" group.
>> To post to this group, send email to algogeeks@googlegroups.com.
>> To unsubscribe from this group, send email to
>> algogeeks+unsubscr...@googlegroups.com.
>> For more options, visit this group at
>> http://groups.google.com/group/algogeeks?hl=en.
>>
>
>  --
> You received this message because you are subscribed to the Google Groups
> "Algorithm Geeks" group.
> To post to this group, send email to algogeeks@googlegroups.com.
> To unsubscribe from this group, send email to
> algogeeks+unsubscr...@googlegroups.com.
> For more options, visit this group at
> http://groups.google.com/group/algogeeks?hl=en.
>

-- 
You received this message because you are subscribed to the Google Groups 
"Algorithm Geeks" group.
To post to this group, send email to algogeeks@googlegroups.com.
To unsubscribe from this group, send email to 
algogeeks+unsubscr...@googlegroups.com.
For more options, visit this group at 
http://groups.google.com/group/algogeeks?hl=en.

Reply via email to