@vicky
your approach doesn't work for  (x1,y1) = (1,2)
                                              (x2,y2) = (2,3)

By your Approach:-
              Ans= sumArray[x2][y2] - sumArray[x1][y1] + ip[x1][y1]=66-18+6=
*54*
But Actual Ans is 6+7+10+11=*34*

On Sun, Aug 12, 2012 at 8:19 PM, ~*~VICKY~*~ <venkat.jun...@gmail.com>wrote:

> Lets build the array for the example you gave.
>
> i/p:
>
> 0 1 2 3
> 4 5  6 7
> 8 9 10 11
>
> (x1,y1) = (0,0)
> (x2,y2) = (1,2)
> sumArray
> 0  1     2    3
> 4  10  18   28
> 12 27  45  66
> (will take O(n^2) to build above array)
> So now when you get coordinates as input, you can calc the sum by
>
> Ans = sumArray[x2][y2] - sumArray[x1][y1] + ip[x1][y1]
>
> For our case it will be Ans = 18-0+0 = 18
>
> Please lemme know if any bugs with the logic.
>
>
> On Sun, Aug 12, 2012 at 6:27 PM, Srividhya Sampath <srisam261...@gmail.com
> > wrote:
>
>>
>> @ Vicky
>>
>> Can yo explain with an illustration ?
>>
>>
>> On Sat, Aug 11, 2012 at 10:07 PM, ~*~VICKY~*~ <venkat.jun...@gmail.com>wrote:
>>
>>> May be you can consider creating a 2d array to pre process and store all
>>> the rectangle sums as a dependent subproblem, the sum of larger rect will
>>> be currValuesAdded+OldRectSum. So when you get the coordinate as input u
>>> can calc the needed sum by subtracting sum of big rect and small rect which
>>> is not included in the given coordinates. This can be called constant time
>>> if u don't include the preprocessing time.
>>>
>>>
>>> On Sat, Aug 11, 2012 at 9:57 PM, adarsh kumar <algog...@gmail.com>wrote:
>>>
>>>> Sum of the integers meaning? Do you mind giving an example test case?
>>>>
>>>> regards.
>>>>
>>>> On Sat, Aug 11, 2012 at 7:10 PM, Srividhya <srisam261...@gmail.com>wrote:
>>>>
>>>>> hi all:)
>>>>>
>>>>> The coordinates of a rectangle will be specified. there is a matrix of
>>>>> integers. yo should find the sum of the integers that fall in the region
>>>>> specified by the  coordinates .
>>>>>
>>>>> The solution to be in constant time .
>>>>>
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>>>
>>>
>>> --
>>> Cheers,
>>>
>>>   Vicky
>>>
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>
>
>
> --
> Cheers,
>
>   Vicky
>
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-- 

--

‘Kailash Bagaria’
B-tech 4th year
Computer Science & Engineering
Indian Institute of Technology, Roorkee
Roorkee, India (247667)

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