what happens when a = 3, d = 5 a, a + d, d +2, a +3 d = 3,8,13,18? Wladimir Araujo Tavares *Federal University of Ceará <http://lia.ufc.br/%7Ewladimir/> Homepage <http://lia.ufc.br/%7Ewladimir/> | Maratona<https://sites.google.com/site/quixadamaratona/>| *
On Thu, Sep 27, 2012 at 8:57 AM, atul anand <atul.87fri...@gmail.com> wrote: > @ashish : here is the generalized equation.... > http://en.wikipedia.org/wiki/Inclusion%E2%80%93exclusion_principle > > note : you need to take LCM of a,a+d,a+2d etc etc........whenever you are > dividing to find count > > On Thu, Sep 27, 2012 at 2:55 AM, ashish pant <asheesh...@gmail.com> wrote: > >> thanks for your reply.. actually i was thinking the same thing.. but I am >> facing problems in finding the unique multiples of a+3d and a+4d as >> applying inclusion exclusion principle in this way is getting too difficult >> due to large no of factors to be added and subtracted.. is der any other >> approach or any way to simplify the process.. >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to algogeeks@googlegroups.com. >> To unsubscribe from this group, send email to >> algogeeks+unsubscr...@googlegroups.com. >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algogeeks@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
