#include<stdio.h>
int main()
{
char str[10]={'g','k'};
char str1[10]="gh";
int i;
for(i=0;str1[i]!=NULL;i++)
printf("%c",str[i]);
getchar();
}
NUll is there in character array also...make clear me...
On Sat, Oct 6, 2012 at 9:22 PM, rahul sharma <rahul23111...@gmail.com>wrote:
> int main()
> {
> char str[10]={'g','k'};
> char str1[10]="gh";
>
>
> printf("%s",str);
> printf("%s",str1);
> getchar();
> }
> then how does this work???
> str printing gk...then NULL is automatically appended in this also...plz
> tell
>
>
> On Sat, Oct 6, 2012 at 6:33 PM, Rathish Kannan <rathishkan...@gmail.com>wrote:
>
>> For string, C appends '\0' internally. hence sizeof(str) returned the
>> value 3.
>> str1 is char array with two character. hence sizeof(str1) returned the
>> value 2.
>>
>> -- RK :)
>>
>>
>> On Sat, Oct 6, 2012 at 5:53 PM, rahul sharma <rahul23111...@gmail.com>wrote:
>>
>>> char str[]="ab";
>>> char str1[]={'a','b'};
>>>
>>> sizeof(str) ...o/p is 3
>>> sizeof(str1)....o/p is 2..
>>>
>>> Why so????
>>> plz explain...
>>>
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