Ok! So I guess now we are talkng my solution. What i do is maintain two pointers i and j, i is the end of the first string and j is the beginning of the second. If both the character match, I calculate the answer for pointers i-1,j+1 and add 1 to the answer for i,j. If they don't match, I simply mark 0 as the answer for i,j. So my table if filled top-down like this. Finally, I return the maximum entry in the table. Need I explain further? If so, feel free. Should I explain what those methods do?
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