*> Any ideas?* Apparently not... *> Any help would be nice* Yes it would. It would also be nice to have some more pertinent information. Like exactly where the error occurs and the exact error message you are getting.
---------------------------------------------------------------------- There are only 10 types of people in the world... Those who know binary and those who don't. ---------------------------------------------------------------------- On Thu, Jun 24, 2010 at 8:39 AM, Milo <milesh...@gmail.com> wrote: > Any help would be nice > > On Jun 17, 4:32 pm, Milo <milesh...@gmail.com> wrote: > > any ideas? > > On Jun 16, 9:44 pm, Milo <milesh...@gmail.com> wrote: > > > > > > > > > I'm trying to consume the following service > > > > > <?xml version="1.0" encoding="utf-8"?> > > > <soap:Envelope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"; > > > xmlns:xsd="http://www.w3.org/2001/XMLSchema"; xmlns:soap="http:// > > > schemas.xmlsoap.org/soap/envelope/"> > > > <soap:Body> > > > <DoIt xmlns="http://tempuri.org/";> > > > <procedure>string</procedure> > > > <args> > > > <string>string</string> > > > <string>string</string> > > > </args> > > > </DoIt> > > > </soap:Body> > > > </soap:Envelope> > > > > > I've cobbled together the following.: --- > > > > > String rtn = ""; > > > SoapObject Request = new > SoapObject(NAME_SPACE, METHOD_NAME); > > > PropertyInfo pi = new PropertyInfo(); > > > > > String [] objectArray = { "string1", "string2", > "string3", > > > "string4"}; > > > > > pi.setName("args"); > > > pi.setValue(objectArray); > > > > > Request.addProperty("procedure", > "actionProcedure"); > > > Request.addProperty(pi); > > > > > SoapSerializationEnvelope soapEnvelope = new > > > SoapSerializationEnvelope(SoapEnvelope.VER11); > > > soapEnvelope.dotNet = true; > > > soapEnvelope.setOutputSoapObject(Request); > > > > > AndroidHttpTransport aht = new > AndroidHttpTransport(URL); > > > try > > > { > > > aht.call(SOAP_ACTION, soapEnvelope); > > > SoapObject resultString = > (SoapObject)soapEnvelope.getResponse(); > > > > > But I'm getting a "Cannot serialize" error... > > > > > Any ideas??? thanks... > > > > > Milo- Hide quoted text - > > > > - Show quoted text - > > -- > You received this message because you are subscribed to the Google > Groups "Android Beginners" group. > > NEW! Try asking and tagging your question on Stack Overflow at > http://stackoverflow.com/questions/tagged/android > > To unsubscribe from this group, send email to > android-beginners+unsubscr...@googlegroups.com<android-beginners%2bunsubscr...@googlegroups.com> > For more options, visit this group at > http://groups.google.com/group/android-beginners?hl=en > -- You received this message because you are subscribed to the Google Groups "Android Beginners" group. NEW! Try asking and tagging your question on Stack Overflow at http://stackoverflow.com/questions/tagged/android To unsubscribe from this group, send email to android-beginners+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/android-beginners?hl=en
