Hi, I'm having some troubles with generics, trying to get the "Type" of my Parameterized class???
Let's begin with a working example... class TestClass<T> { Type type; public TestClass() { type = getSuperclassTypeParameter(getClass()); } static Type getSuperclassTypeParameter(Class<?> subclass) { Type superclass = subclass.getGenericSuperclass(); if (superclass instanceof Class) { throw new RuntimeException("Missing type parameter."); } ParameterizedType parameterized = (ParameterizedType) superclass; return parameterized.getActualTypeArguments()[0]; } } Whit this code, I can get at runtime, the Type of T (like TestClass<String> will return a String type). My problem is when I have a generic class extending another generic class. class AsyncRequest<T> extends AsynTask<String, Void, AsyncResponse<T>> { Type type; public AsyncRequest() { type = getSuperclassTypeParameter(getClass()); } static Type getSuperclassTypeParameter(Class<?> subclass); } In this case, with getSuperclassTypeParameter() I get the parameterized types of AsyncTask, and not of my own Class AsyncRequest... (parameterized.getActualTypeArguments()[0] is a String type). Anyone has some ideia of how I can get the Type of T of my own Class??? Thanks in advance... LĂșcio Maciel luci...@gmail.com -- You received this message because you are subscribed to the Google Groups "Android Developers" group. To post to this group, send email to android-developers@googlegroups.com To unsubscribe from this group, send email to android-developers+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/android-developers?hl=en