Hi,
I'm sure this question has been answered before but I'm not sure how
to phrase it well enough to find it in the archives.
I want to match to inputs an INT such as ' 170 \n'
and an AMOUNT such as ' $ 170.00 ' (unfortunately there is
occasionally a space before the amount)
The following grammar works for ' $ 170.00 ' but not for ' 170 ' it
sees the space and tries to match the AMOUNT and the output
'mismatched character ' ' expecting '.' ' is provided. Reading
through the antlr reference book, it looks like there are a number of
ways to possibly handle this but I'm not sure how best to approach it.
grammar testing;
start :
(AMOUNT
| INT
| NEW_LINE)+;
fragment DIGIT : '0'..'9';
AMOUNT : '$'? SPACE? DIGIT+ (','DIGIT+)? '.' DIGIT DIGIT;
INT : DIGIT+ (','DIGIT+)?;
NEW_LINE
: ('\r'?'\n');
WS : (SPACE |'\t'|'\u000C')
{$channel=HIDDEN;};
fragment SPACE
: ' ';
Thanks,
Richard
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