Am Sun, 13 Mar 2011 22:58:21 -0400
schrieb Dave Reisner <d...@falconindy.com>:
> Absolutely not. ${var} is identical to $var in every way except one:
>
> $varfoo != ${var}foo
>
> The curly braces otherwise provide zero differentiation in expansion
> rules when used in this fashion.
You're wrong again. ${variable} is the same as "$variable".
From `man bash`:
${parameter}
The value of parameter is substituted. The braces are
required when parameter is a positional parameter with more than one
digit, or when parameter is followed by a character which is not to be
interpreted as part of its name.
Heiko
