let $test :=
element div0{
attribute id { 4 },
element div1 {
attribute id { 3 },
element div1 {
attribute id { 2 },
element para {
attribute id { 1 },
element child { }
}
}
}
}
I want to get the "smallest" div1 for a given child. this is, the <div1
id=2> element.
As far as I've understood the answers given here, reverse axes are ordered
from the context node, so the expression
$test//child/ancestor-or-self::div1[1] will get me what i want, while
$test//child/parent() will give me <para id=1>
Needless to say, my data is not particularly well behaved :)
Thanks!
On Wed, Apr 16, 2014 at 3:16 PM, David Rudel <fwqhg...@gmail.com> wrote:
> I apologize if I'm being dense, but I don't understand how the nearest
> ancestor can be anything other than the parent. Could you please give
> an example?
>
> I just want to make sure I haven't sent you off with the wrong
> expression for your intended usage.
>
> On Wed, Apr 16, 2014 at 8:48 PM, José Tomás Atria <jtat...@gmail.com>
> wrote:
> > Thank you all for your answers.
> >
> > I was just tryig to determine if $test/ancestor::element()[1] would be
> the
> > correct way of getting the nearest ancestor, as I couldn't find whether
> axes
> > were ordered or not in the xpath specification.
> >
> > Thanks!
> >
> > ps: Parent doesn't apply, because the relevant node is not always the
> > parent, but the first node with a given name.
> >
> >
> > On Wed, Apr 16, 2014 at 2:45 PM, David Rudel <fwqhg...@gmail.com> wrote:
> >>
> >> Mr. Atria,
> >> You left out a key element from the answer you got from stack overflow.
> >>
> >> Note that Dimitre's response used a filter expression
> >> (path expression) [predicate]
> >>
> >> not a simple path expression
> >>
> >> The ()s are critical.
> >>
> >> $test//child/ancestor-or-self::test[ last() ]
> >>
> >> is very different from
> >>
> >> ($test//child/ancestor-or-self::test)[ last() ]
> >>
> >> The ancestor axis is a reverse axis, but when the xpath expression is
> >> complete, the sequence of nodes are then put in document order
> >> regardless of what order the last axis had.
> >>
> >> In any event, I don't understand what is wrong with simply
> >> $test/ancestor::element()[1]
> >>
> >> Perhaps I don't understand your question (which is simpler than the
> >> Stack Overflow question you linked to). But if you are just looking
> >> for the nearest ancestor element, then it seems that
> >> $test/ancestor::element()[1] should give it to you.
> >
> >
> >
> >
> > --
> > entia non sunt multiplicanda praeter necessitatem
>
>
>
> --
>
> "A false conclusion, once arrived at and widely accepted is not
> dislodged easily, and the less it is understood, the more tenaciously
> it is held." - Cantor's Law of Preservation of Ignorance.
>
--
entia non sunt multiplicanda praeter necessitatem
