Thank You for correcting me, indeed binding operator has higher precedence than other operators. I apologise for making a hotch potch out of the entire solution. I confused it thinking you posted this issue, and didnt see that you were the one answering it.
Yes, your answer is much better. Thanks Soham ----- Original Message ---- From: Uri Guttman <u...@stemsystems.com> To: Soham Das <soham...@yahoo.co.in> Cc: beginners@perl.org Sent: Thursday, 16 July, 2009 11:30:31 AM Subject: Re: Fw: Modifiers on the right side of the statement >>>>> "SD" == Soham Das <soham...@yahoo.co.in> writes: SD> ----- Forwarded Message ---- SD> From: Soham Das <soham...@yahoo.co.in> SD> To: Uri Guttman <u...@stemsystems.com> SD> Sent: Thursday, 16 July, 2009 11:23:29 AM SD> Subject: Re: Modifiers on the right side of the statement SD> I believe its because =~ has the highest priorty... the term is precedence, not priority. and =~ is not the highest but it is higher than a builtin function which takes an arg. and this has been covered in my email you quoted below. uri -- Uri Guttman ------ u...@stemsystems.com -------- http://www.sysarch.com -- ----- Perl Code Review , Architecture, Development, Training, Support ------ --------- Free Perl Training --- http://perlhunter.com/college.html --------- --------- Gourmet Hot Cocoa Mix ---- http://bestfriendscocoa.com --------- -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/ See the Web's breaking stories, chosen by people like you. Check out Yahoo! Buzz. http://in.buzz.yahoo.com/ -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/