I have two scalars created from passed params. i want to create a third variable by subtracting the two scalars. how can i do this? i have tried:
$need = $dif - $score but i get a 500 server error and my error log says that i cannot use the '-' operator on a scalar variable. can anyone suggesta better way? cheers -- Matthew Harrison Internet/Network Services Administrator Peanut-Butter Cheesecake Hosting Services Genstate www.peanutbuttercheesecake.co.uk -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
