Michael Turner wrote: > > OK, here is a "real" beginners question, but interesting nonetheless: > > Sample code: > > $b = 1; > $b = $b++; > > Result: > > $b = 1 > > Which strikes me as a little surprising. Shouldn't the result be 2? What > is happening?
The simple answer is *DON'T DO THAT*. :-) In C, from whence the pre and post increment are derived, this behavour is undefined. In other words, if you are going to use pre or post increment on a variable, don't use that variable elsewhere in the same expression. When you post increment a variable, the value of that variable is returned and then the value is incremented. When you pre increment a variable, the value is incremented and the new value is returned. John -- use Perl; program fulfillment -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
