[sorry about that first post, I got ^X-happy]
On Nov 5, Dan Anderson said:
>use Data::Dump qw(dump);
>foo->bar qw(foo bar);
>Am I correct in assuming that if I have a subroutine foo (or method if
>called with a package name), and I use qw() it takes all words seperated
>by spaces, and passes them in as arguments.
>
>So: foo->bar qw(foo bar); is equivalent to foo->bar("foo","bar"); ?
The qw() operator changes your source code at compile-time, which is why
you can say
$object->method qw(...)
when ordinarily you'd need
$object->method(...)
When you use qw(this that those), Perl changes that to
('this', 'that', 'those')
Perl splits the qw(...) on spaces, and returns the raw data,
single-quoted. This means no variables. You can't even escape a space:
qw( abc\ def )
becomes
('abc\\', 'def')
That is all.
--
Jeff "japhy" Pinyan [EMAIL PROTECTED] http://www.pobox.com/~japhy/
RPI Acacia brother #734 http://www.perlmonks.org/ http://www.cpan.org/
<stu> what does y/// stand for? <tenderpuss> why, yansliterate of course.
[ I'm looking for programming work. If you like my work, let me know. ]
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