Re: Is foo qw (arg1 arg2) equivalent to foo (arg1, arg2)?

[Dan Anderson]

> Dan> So: foo->bar qw(foo bar); is equivalent to foo->bar("foo","bar"); ?
> 
> Only in recent Perls.  

Do you know exactly how recent?  Are we talking 5 or better or 3 or
better?

Thanks in advance,

-Dan

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