This worked perfectly! Thanks.
--- James Edward Gray II <[EMAIL PROTECTED]>
wrote:
> On Mar 8, 2004, at 4:19 PM, Stuart White wrote:
>
> > Conceptually, what you say the result is, is what
> I
> > want, thanks. When I read it though, without the
> > comment, I'd guess that the program would pair
> those
> > words like so:
> > dog:cat, dog:lizard, dog:wombat
> > with dog:lizard overwriting dog:cat, and
> dog:wombat
> > overwriting dog:lizard.
> > I seem to remember an example like this from the
> Llama
> > book.
> >
> > However, absent my confusion, and given you're
> > correct, would this:
> > foreach (@words) {
> >> $seen{$_}++;
>
> This is where the work gets done, yes. In English
> it reads, for every
> word in the array, add one to the corresponding hash
> value under that
> key. That will give you a hash with keys for all
> the words. Their
> values will be the number of times that word
> appeared in the array.
> That's often useful, but in this case we can safely
> discard the values
> as the keys alone provide our answer. Make sense?
>
> James
>
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