Charlotte Hee wrote:
>
> For a single record I can see how that works but let's say I have
> 4 or 5 employees and I have the employee information for each one
> (assumed). Now I want to build a record for each employee in a loop like
> this:
>
> @names = ('Jason','Aria','Samir','Owen');
>
> foreach $na ( @names ) {
So all the records differ only in name, and all other parameters stay the same?
> $record = {
> NAME => $na,
> EMPNO => $emp_no,
> TITLE => $title,
> AGE => $age,
> SALARY => $salary,
> PALS => [ $friend_list ],
> };
>
> # store record
> $byname{ $record->{NAME} } = $record;
>
> }
>
> Now I want to add something later, after the record for the employee has
> been created. For example, I want to add the phone for Owen.
> When I try the following I get "can't use undefined value...".
Since you don't seem to be showing us the code you are actually using, we are
somewhat at a disadvantage. ONe thing you should not, though. Since the nested
hashes should be storedonly by reference, you should use the derefereing operator
-> to get at least the fianl element.
> $byname{ Owen }{ PHONE } = '999-9999';
Should be:
$byname{ Owen }->{ PHONE } = '999-9999';
are you using strict? The code above should cause an error, not just an
uninitialized variable warning. You really should put:
use strict;
use warnings;
at the top of the script, and clean up the errors returned before you try to take
on multidimensional structure problems. Houses built on sand cannot be expected
to stand.
Joseph
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