> The problem is that the second part of the substitution (HI) is not > taken as a regex, but as a string, which is to mean that you're trying > to replace "\n" with "HI\n". > > If you were using > > s/ > (\n) > /HI/xisg; > > instead, you wouldn't have that problem. > > > Now that we've been through the problem, let me tell you > about an easier > way to do it: > > s/\n/HI/g; > > There :-) Much simpler, isn't it? :-) >
Without wanting to sound like a wiseguy, wouldnÂt this be even simpler: chomp; If you want to strip more than the \n, a regex would be more appropriate, but if youÂre talking about the trailing newline only, chomp might be the easiest (and probably fastest) solution. Just my 5 cent, Philipp -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] <http://learn.perl.org/> <http://learn.perl.org/first-response>
