On Friday 02 July 2004 15:07, Randy W. Sims wrote:
> Wiggins d Anconia wrote:
> >
> > You can take the list in a scalar context, or force it into a
> > scalar context, such as,
> >
> > my $num = keys %{ $printers{jobs} };
> >
> > or the more verbose,
> >
> > my $num = scalar keys %{ $printers{jobs} };
> >
> > 'values' works in place of 'keys' since it is a 1-to-1
> > relationship, keys is my preferred.
>
> Don't forget the oft forgot and more efficient
>
> print scalar %hash;
>
> eg.
>
> my %hash = (
> A => 1, B => 2, C => 3
> );
> print scalar %hash;
> => 3/8
Neither the 3 nor the 8 nor 3 divided by 8 has any relation to the
number of keys or number of values in the hash.
John
--
use Perl;
program
fulfillment
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