Bob Showalter wrote:
Flemming Greve Skovengaard wrote:
printf ("%02d/%02d/%02d\n", $month + 1, $day, $year - 100);
# Only works when $year > 1999.
And when $year <= 2099 :~)
Stick to $year % 100;
Yes, you are correct. Your solution is fool proof.
--
Flemming Greve Skovengaard FAITH, n.
a.k.a Greven, TuxPower Belief without evidence in what is told
<[EMAIL PROTECTED]> by one who speaks without knowledge,
4112.38 BogoMIPS of things without parallel.
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