I have this code:
my ($month, $day, $year) = (localtime)[4,3,5]; printf ("%02d/%02d/%02d\n", $month+1,$day,$year+1900);
which gives me
08/16/2004
what I want is 08/16/04.
"perldoc -f localtime" describes very clearly how you get a two digit year. It's advisable to study the docs for the functions you are using before asking others for help.
-- Gunnar Hjalmarsson Email: http://www.gunnar.cc/cgi-bin/contact.pl
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