> So. In the context of subroutine arguments, you're generally passing in > one or more arguments. If you're only passing one, then you're right --
> my $arg = @_; So what wiggins saying, here $arg has now 1 ? > my $arg = shift; here $arg has now the value of the first element(argument) ? > my $arg = $_; here $arg gets default value? > -- are all equivalent. I agree. :) [snip] -- Cheers, SanoBabu -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] <http://learn.perl.org/> <http://learn.perl.org/first-response>
