> > So. In the context of subroutine arguments, you're generally passing in > > one or more arguments. If you're only passing one, then you're right -- > > > my $arg = @_; > So what wiggins saying, here $arg has now 1 ? >
Yes. It is the length of the array, or "a list taken in scalar context". > > my $arg = shift; > here $arg has now the value of the first element(argument) ? > > > my $arg = $_; > here $arg gets default value? Ha, didn't even notice that one, yep $_ is definitely different than $_[0], which is what the others would have. > > > -- are all equivalent. > > I agree. :) > ?? You are agreeing that they are, or aren't? They definitely aren't. > [snip] > -- > Cheers, > SanoBabu > http://danconia.org -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] <http://learn.perl.org/> <http://learn.perl.org/first-response>
