Offer Kaye wrote:
On Thu, 31 Mar 2005 12:16:21 -0800, John W. Krahn wrote:
And yet in your examples you use @ in double quoted strings four times
without
escaping it (hint: m// and s/// interpolate like double quoted strings.)
Ah, but there is an important difference - in all the cases I wrote,
the characters following the '@' sign could not be a legal variable
name,
$ perl -le' @) = qw/ a b c d /; print for @) '
a
b
c
d
$ perl -le' @/ = qw/ a b c d /; print for @/ '
a
b
c
d
$ perl -le' @" = qw/ a b c d /; print for @" '
a
b
c
d
so there was no need to escape the '@'. For example, the code
you wrote above could be written without the "\" before the "@":
1 while $str =~ s/(?<=@)(.+?)_/$1./;
Go ahead and try it - I promise you it works.
I don't know where this is documented*, so I can't prove this, but at
least as far as the code, it works. So do my solutions, BTW - I tried
them before posting.
* If you or anyone else knows where this is documented, I'd love to
know the location for future reference. Thanks.
perldoc perlop
[snip]
Quote and Quote-like Operators
[snip]
Interpolating an array or slice interpolates the elements in order,
separated by the value of $", so is equivalent to interpolating "join $",
@array". "Punctuation" arrays such as "@+" are only interpolated if
the name is enclosed in braces "@{+}".
John
--
use Perl;
program
fulfillment
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