On 10/19/06, Robert Hicks <[EMAIL PROTECTED]> wrote:
I am currently building the IF statement like:
if ($project_name eq 'Proj1' || $project_name eq '' && $task_name eq '')
Because logical-and is higher precedence than logical-or, that
condition is the same as this:
$project_name eq 'Proj1' || ($project_name eq '' && $task_name eq '')
Is that what you want? I think you might be expecting different grouping:
($project_name eq 'Proj1' || $project_name eq '') && $task_name eq ''
That works but I was wondering if I can do this:
if ($project_name eq ('Proj1' || '') && $task_name eq '')
Maybe someday in Perl 6, but not here today. Of course, you could use
a pattern match instead of string equality to do something similar:
$project_name =~ /^(Proj1)?$/ and $task_name eq ''
Or you could use a subroutine:
&any_match($project_name, 'Proj1', '') and $task_name eq ''
TMTOWTDI. I'm sure other variants will be posted as well. Hope this helps!
--Tom Phoenix
Stonehenge Perl Training
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