Michael Alipio am Sonntag, 21. Januar 2007 04:08: > Hi, Hi Michael
> my $string = 'vd=root,status='; > > #Now, I want to transform it into: > 'vd=root;status=' > #That is replace the comma(,) between root and status with semicolon (;); > > $string =~ s/vd=\w+(,)/;/; > print $string,"\n"; > > #And it prints: > > ;status= > > Can you tell me why it has ate up vd= as well? Because everything matched - that is: vd=\w+(,) - is replaced with the semicolon. You seem to misunderstand the meaning of the capturing parenthesis '()' on the left part of the substitution: They do not indicate the part of the string that is to be replaced; replaced is what the left side of the substitution matches. > And how to get around with it.. One way is: $string =~ s/(vd=\w+),/$1;/; There are several man pages, where also the capturing parenthesis and the $1.. $n variables are explained: perldoc perlre perldoc perlretut perldoc perlrequick Hope this helps! Dani -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/
