David Abrahams <[EMAIL PROTECTED]> writes: | I disagree with your conclusion. As I've said elsewhere, &k can be a | compile-time constant in the same way that &X::k is a compile-time | constant.
Certainly, you've said that. But that assertion by itself does not constitute a proof of the well-foundness of the attempted analogy or whether the analogy actually constitutes a proof. -- Gaby _______________________________________________ Unsubscribe & other changes: http://lists.boost.org/mailman/listinfo.cgi/boost
