Close, but not quite -- the /m modifier turns on multiline matching -- allowing ^ and $ to match newlines embedded within the string.
I think you're thinking of the /s modifier, which allows '.' to match newline chars like any other. On Wed, 20 Feb 2002, Greg Marr wrote: > At 12:03 PM 02/20/2002, Peter R. Wood wrote: > > > So, I think you really want: > > > > > > if ( $query =~ m#/\*\+\s+(.+?)\s+\*/# ) > > > >Ok, so let me make sure I am reading your pattern correctly: > > > >(.+?) > followed by one or more non-newline characters, which will > >match up > >to the first occurrance of the next character after the ?, the > >contents of > >the match being placed in $1 > > Not exactly. Just .+, without the ?, will match the largest number, > greater than zero, of non-newline characters (assuming you're not > using the m modifier) that still causes the rest of the pattern to > match. With the ?, .+?, it will match the smallest number, greater > than zero, of non-newline characters that still causes the rest of > the pattern to match. > > Using this string: > /*+ foo bar baz *//*+ foo bar baz */ > Without the ?, it would match "foo bar baz *//*+ foo bar baz". With > the ?, it would match "foo bar baz". > > -- Steve Reppucci [EMAIL PROTECTED] | Logical Choice Software http://logsoft.com/ | =-=-=-=-=-=-=-=-=-=- My God! What have I done? -=-=-=-=-=-=-=-=-=-=
