Bob Proulx <b...@proulx.com> writes:

> Neither of those produce any output.
>
>   $ printf '%d\n' ""
>   0

Since the command substitution is not quoted the result of the expansion
is subject to field splitting, thus expands to nothing at all instead of
a single empty argument.

Andreas.

-- 
Andreas Schwab, sch...@linux-m68k.org
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"And now for something completely different."

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