Andreas Schwab wrote:
> Bob Proulx writes:
> > Neither of those produce any output.
> >
> >   $ printf '%d\n' ""
> >   0
> 
> Since the command substitution is not quoted the result of the expansion
> is subject to field splitting, thus expands to nothing at all instead of
> a single empty argument.

Ah, yes, you are right of course.  I should have said:

  $ printf '%d\n'
  0

Thanks!
Bob

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