pass the array as reference in the function.
void chArray(int *array)
{
array[0] = 4;
}
int main(void)
{
int arr[] = {1,2,3};
...
chArray(&arr[0]);
...
return 0;
}
Em 2/4/2009 10:41, rsashwinkumar escreveu:
>
> this may be very basic but plz., help
>
> How to pass an array(1 Dimensional) to a function, multiply its
> elements by 2 and return to main function and assign to another array...
>
> Plz., help urgent...
>
>
