so, passing a reference in c++ is just the equiv of a pointer?
Thanks, Tyler Littlefield Web: tysdomain.com email: [email protected] My programs don't have bugs, they're called randomly added features. ----- Original Message ----- From: Michael Comperchio To: [email protected] Sent: Thursday, April 02, 2009 2:07 PM Subject: Re: [c-prog] returning arrays Remembering the reason for references in c++ is to hide the implementation of things (whatever things might be). References are part of the OOP design. The caller has to know nothing about the function being called. Simply pass in the value, and, since the compiler can see that it needs a pointer because of the function footprint, let the compiler convert it to a pointer! Don't sweat the small stuff, in fact, don't sweat anything at all. You'll save a lot on deodorant - Forrest Gump Michael Comperchio [email protected] On Apr 2, 2009, at 1:19 PM, Tyler Littlefield wrote: > ok. I was thinking c++, you can pass reference which is diff from a > pointer. > > Thanks, > Tyler Littlefield > Web: tysdomain.com > email: [email protected] > My programs don't have bugs, they're called randomly added features. > > ----- Original Message ----- > From: Michael Comperchio > To: [email protected] > Sent: Thursday, April 02, 2009 11:11 AM > Subject: Re: [c-prog] returning arrays > > a hunting dog! > > A pointer is something that is pointing to a place in memory.... hence > pointer. When I learned 'C' (dinosaurs still on earth) I was taught > there are two ways to pass something to a function. By Value, and By > Reference. When I pass by value, a copy of the original data is pushed > on the stack, and the calling function pops it off. Because it's a > copy > only, I can manipulate it to my hearts content, and not change the > original. When I pass 'by reference' I push the memory location which > references (points to, hence pointer) the original data. When my > function pops the reference off the top of the stack I can manipulate > what is pointed to by the memory address, > > I miss coding in c for a living. there is sooooo much fun to be had > with it! > > Michael > > Commander: "I assure you the project will be completed on time!" > Darth: "The emperor does not share your optimistic appraisal of the > situation" > > On Apr 2, 2009, at 10:51 AM, Allison Vollmann wrote: > > > and what is an pointer? > > > > Em 2/4/2009 11:41, Tyler Littlefield escreveu: > > > > > > as reference? that's as pointer. > > > > > > Thanks, > > > Tyler Littlefield > > > Web: tysdomain.com > > > email: [email protected] <mailto:tyler%40tysdomain.com> > > > My programs don't have bugs, they're called randomly added > features. > > > > > > ----- Original Message ----- > > > From: Allison Vollmann > > > To: [email protected] <mailto:c-prog%40yahoogroups.com> > > > Sent: Thursday, April 02, 2009 8:09 AM > > > Subject: Re: [c-prog] returning arrays > > > > > > pass the array as reference in the function. > > > > > > void chArray(int *array) > > > { > > > array[0] = 4; > > > } > > > > > > int main(void) > > > { > > > int arr[] = {1,2,3}; > > > ... > > > chArray(&arr[0]); > > > ... > > > return 0; > > > } > > > > > > Em 2/4/2009 10:41, rsashwinkumar escreveu: > > > > > > > > this may be very basic but plz., help > > > > > > > > How to pass an array(1 Dimensional) to a function, multiply its > > > > elements by 2 and return to main function and assign to another > > array... > > > > > > > > Plz., help urgent... > > > > > > > > > > > > > > [Non-text portions of this message have been removed] > > > > > > > > > > > > [Non-text portions of this message have been removed] > > [Non-text portions of this message have been removed]
