On Tue, Jan 12, 2010 at 7:06 AM, John <[email protected]> wrote:
> --- In [email protected], John Gaughan <j...@...> wrote:
>>
>> Try initializing the memory to which newstr points before trying to use
>> it: this includes getting its length.
>
> 'getting' -> 'setting', or am I reading it wrong?
You're reading it wrong.
They're doing the equivalent of:
const char* str = "Hello world";
char* newstr = malloc(strlen(str));
printf("%d\n%d\n", strlen(str), strlen(newstr));
What is the contents of newstr at the printf() stage? (And,
incidentall,y why isn't it big enough to contain 'str'?)
Hint:
It's missing an equivalent memcpy(newstr, str, strlen(str)) step.
--
PJH
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