You have just allocated memory which contains garbage or nothing.
Strlen will try to print from the first address until it finds NULL. So when
you say strlen(newstr) it is giving 3 which is a undefined value.
For example let us a take c prog:
Main()
{
Char *p;
Printf("%d",strlen(p));
}
Out: 3 which is an undefined value.
Let us give char *p = NULL;
Now try printing it will give segmentation fault. Because the pointer is
pointing to nothing and your collecting length from NULL.
Char *str = "Hello World";
Char *newstr = new char[strlen(str)];
After this assign some thing to newstr and try to print the strlen.
Thanks & Regards,
Vijaya Rama Raju . Jampana,
________________________________
From: c-prog@yahoogroups.com [mailto:c-p...@yahoogroups.com] On Behalf Of CK
Sent: Monday, January 11, 2010 10:49 AM
To: c-prog@yahoogroups.com
Subject: [c-prog] Help with new char array
I'm trying to define dynamic array using "new".
Char *str = "Hello World";
Char *newstr = new char[strlen(str)];
Cout<<strlen(str)<<endl;
Cout<<strlen(newstr)<<endl;
Strlen(str) = 11;
Strlen(newstr) = 3;
Why is it only 3? What is wrong? Can somebody help me with this?
Thank you
CK
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