You're going to wince when you see this ...
$session->id()
http://api.cakephp.org/1.2/class_session_component.html#e1692bdb30d589bc95f3173d20ba6295
Yeah, it's odd that debug($session) shows an empty 'id' field and that
you need to use the method. I'm sure it's much safer that way but then
why the array field?
Because, if i do
$session->id('foobar') // the method also accepts a param to set the var
debug($session);
the id field is still empty.
On Tue, Apr 22, 2008 at 1:04 PM, MonkeyGirl <[EMAIL PROTECTED]> wrote:
>
> Hi again!
>
> I'm using the session component, as documented at
> http://manual.cakephp.org/view/173/sessions , and it's storing and
> retrieving all the session variables I set just fine.
>
> However, I'm trying to find the session ID - or anything else that's
> unique to each visitor, but doesn't change each time they load a new
> page - and I'm getting a bit stuck here.
>
> I've tried echoing out PHP's session ID, as documented at
> www.php.net/session_id
> , but it seems to change each time a page is loaded. I'm assuming
> CakePHP is doing magical things with sessions that I just shouldn't
> interfere with lest I break something, but please correct me if I'm
> wrong about that.
>
> So I looked at what $this->Session is storing, figuring that maybe
> it's storing some kind of consistent ID somewhere. The closest I could
> find was $this->Session->_userAgent , but that appears to just be a
> hash of the browser name, nothing else, as someone else using the same
> browser even on a different network will get the same value.
>
> So is there anything that acts like a regular, consistent session ID?
>
> If not, I can just set a hash of the user's browser, IP address, and
> the current timestamp at the exact moment they visit the site and set
> that as a regular session variable (ie each time the user loads a
> page, check for this session variable, and if it's not set, generate
> and set it), but that seems a bit long winded and a case of
> reinventing the wheel when this is exactly what session IDs are for.
>
> Thanks for any suggestions,
> Zoe.
> >
>
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