On Thu, Feb 19, 2009 at 1:24 PM, Stu <greenmushroo...@gmail.com> wrote: > > @Brian > > Sorry man, I appreciate the help, didn't quite understand what you > meant by that.
No biggie. I thought that was pretty funny. > the variable is set, that I know. (I hard coded values in it for > testing purposes) > > And the error I get is a Parse error for a missing " ) ". which is > strange because I can tell for sure it's not the case. I think I see it now. Aside from the missing $ that mscdex noticed, you've got an extra quote at the end and it appears that you're trying to concatenate strings in this 1st example: var paginate = array('conditions' =>array('Group.site_id = '. $variable .'')); I'm wondering if you did the same when using the => notation. It should be: var $paginate = array( 'conditions' => array( 'Group.site_id' => $variable ) ); --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "CakePHP" group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~----------~----~----~----~------~----~------~--~---