Oh, the clue train just pulled in. You're trying to use a variable when setting the class var $paginate. You can't do that. What you can do, though, is adjust the $paginate var in your method/action.
So, if you have other stuff to put in $paginate ('order', 'limit', etc.) go ahead and do so. Then in your method, do: $this->paginate['conditions'] = array('Group.site_id' => $variable); Obviously, if you already have other conditions, you'll want to append them: $this->paginate['conditions'][] = array('Group.site_id' => $variable); On Thu, Feb 19, 2009 at 2:07 PM, Stu <greenmushroo...@gmail.com> wrote: > > Well, this is interesting: > > var $paginate = array( > 'conditions' => array( > 'Group.site_id' => $variable > ) > ); > > this no longer gives me a missing " ) " parse error, but now I get > this: > > Parse error: parse error in C:\web-dev\www\TelHD\controllers > \group_details_controller.php on line 9 > > and line 9 would be this bad boy: 'Group.site_id' => $variable > > On the other hand if I try this: > > var $paginate = array( > 'conditions' => array( > 'Group.site_id' => 28 > ) > ); > > It works great... > > No doubts the problem comes from my variable now. > > > > > > > --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "CakePHP" group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~----------~----~----~----~------~----~------~--~---