Sorry, I don't know. You might get a better response from the jquery
google group. There are a lot of people who are very helpful with it.
Ask how to mix UITab content between local page content and remote.
On Thu, Jul 16, 2009 at 1:30 PM, havanna<thomas.blas...@diacs.de> wrote:
>
> Hi Brian,
>
> thank you again for your answer. I think I comming a step forward. I
> thought also yesterday, that the ajax call will call my other view.
> Now I think my problem is the ui tab.
> At ui tabs you can include your content from the view - that works for
> tab1 to tab4. It's also possible to say that the content come from an
> ajax call ( remote: true ). But I don't know, how to combine this
> togehter:
>
> <script type="text/javascript">
> $(function() {
> $("#tabs").tabs();
> $('#tabs').tabs(5)({ remote: true }); // this doesn't work
> });
> </script>
>
> Regards Thomas
>
> On 16 Jul., 17:28, brian <bally.z...@gmail.com> wrote:
>> On Wed, Jul 15, 2009 at 5:04 PM,havanna<thomas.blas...@diacs.de> wrote:
>>
>> > Hi Brian,
>> > thank you for your answer.
>>
>> > With $this->contain => false I'm using the shortform (see on
>> >http://book.cakephp.org/view/474/Containable).
>>
>> Yes, it's the short form to tell Cake not to bother invoking
>> Containable. So there's no point in attaching it at all. You could
>> simply use 'recursive' => -1 instead.
>>
>> > I tried your changes. The errors changed: now in my view the vars
>> > which I set in the controller are unknown: Undefined variable:
>> > Objektnummer.
>>
>> > Is it right, that the view is the same as for tab 1 to 4 or need I an
>> > element to display my variables?
>>
>> Yes, you need to have a view for each. Think of it as a normal request
>> to the server, but no layout is used. Each tab has a link to some
>> controller action and those actions each have their own view.
> >
>
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