IIRC, $('#tabs').tabs() should be sufficient, as long as one of your
<LI> contains a remote URL.
For your fifth tab, try using the following:
<li>
<a href="/admin/attachments/getlist/<?php echo $this->data
['Posts']['id']; ?>">
</a>
</li>
Note that I removed the <span> there.
It should call /admin/attachments/getlist/XXX when the fifth tab is
clicked/activated.
On Jul 17, 12:30 am, havanna <thomas.blas...@diacs.de> wrote:
> Hi Brian,
>
> thank you again for your answer. I think I comming a step forward. I
> thought also yesterday, that the ajax call will call my other view.
> Now I think my problem is the ui tab.
> At ui tabs you can include your content from the view - that works for
> tab1 to tab4. It's also possible to say that the content come from an
> ajax call ( remote: true ). But I don't know, how to combine this
> togehter:
>
> <script type="text/javascript">
> $(function() {
> $("#tabs").tabs();
> $('#tabs').tabs(5)({ remote: true }); // this doesn't work
> });
> </script>
>
> Regards Thomas
>
> On 16 Jul., 17:28, brian <bally.z...@gmail.com> wrote:
>
> > On Wed, Jul 15, 2009 at 5:04 PM,havanna<thomas.blas...@diacs.de> wrote:
>
> > > Hi Brian,
> > > thank you for your answer.
>
> > > With $this->contain => false I'm using the shortform (see on
> > >http://book.cakephp.org/view/474/Containable).
>
> > Yes, it's the short form to tell Cake not to bother invoking
> > Containable. So there's no point in attaching it at all. You could
> > simply use 'recursive' => -1 instead.
>
> > > I tried your changes. The errors changed: now in my view the vars
> > > which I set in the controller are unknown: Undefined variable:
> > > Objektnummer.
>
> > > Is it right, that the view is the same as for tab 1 to 4 or need I an
> > > element to display my variables?
>
> > Yes, you need to have a view for each. Think of it as a normal request
> > to the server, but no layout is used. Each tab has a link to some
> > controller action and those actions each have their own view.
>
>
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