Yeah, I know, it's grand that it doesn't if you don't initialize them like 
I do.

But how do I make it touch my object, is the question? :)

On Thursday, 17 May 2012 10:56:40 UTC+2, Krzysztof Koźmic wrote:
>
>  It works as expected.
>
> Windsor never touches your object.
>
> @K
>
> On 16/05/2012 10:34 PM, Henrik wrote: 
>
> Here: https://gist.github.com/2710007
>
> On Tuesday, 15 May 2012 22:27:42 UTC+2, Krzysztof Koźmic wrote: 
>>
>>  I'm not sure I understand.
>>
>> Do you have a failing test to demonstrate it?
>>
>> On 16/05/2012 6:06 AM, Henrik Feldt wrote: 
>>
>>  If it is resolved once, yes, but not otherwise.
>>
>>  
>>
>> The problem is the otherwise. How do I do then?
>>
>>  
>>  
>> *From:* [email protected] [
>> mailto:[email protected]<[email protected]>]
>>  
>> *On Behalf Of *Krzysztof Kozmic
>> *Sent:* den 15 maj 2012 12:02
>> *To:* [email protected]
>> *Subject:* Re: Windsor w/ BackgroundFactoryMethod
>>  
>>  
>>
>> if it's IDisposable it will get disposed
>>
>> On 13/05/2012 10:24 AM, Henrik Feldt wrote: 
>>
>> bump
>>
>>  
>>
>> *From:* [email protected] [
>> mailto:[email protected]<[email protected]>]
>>  
>> *On Behalf Of *Henrik
>> *Sent:* den 9 maj 2012 00:47
>> *To:* [email protected]
>> *Subject:* Windsor w/ BackgroundFactoryMethod
>>
>>  
>>
>> I'm looking to initialize a component on a background thread, so I hacked 
>> something together. It looks like this:
>>
>> https://gist.github.com/2640092
>>
>> It works really nice, except that of course the component isn't being 
>> disposed unless something else that depends on it is resolved, meaning 
>> there's a live component needing disposing which isn't being disposed.
>>
>> Where would I jack into Windsor 3 to provide a piece of logic stating, 
>> that for this type of handler/component/burden (?) when the 
>> container/kernel is being disposed, also perform a resolve and then release 
>> call, for this component?
>>
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