I do think Scott does a pretty good job explaining the concepts behind
ACL wildcard bit masking. As he says in the VOD, one of the reasons
this methodology is hard to grasp is that we aren't introduced to this
concept during our CCNA studies - it's a bit of a paradigm shift for
us. Having a good eye for patterns really helps when working through
the exercises though - of course even the exercises with 50 network
addresses can usually be simplified into 4 to 6 basic groupings so
it's not that bad if you can take the list of addresses and generally
rearrange the order in your head so that things are more obvious.
Just remember: Practice, practice, practice!
Also, this question gets asked often enough on this list that it's a
great place to practice working through the examples given until
someone answers the question correctly.
Good luck,
Michael
On Mon, Jun 8, 2009 at 2:53 PM, Joe Astorino <[email protected]
<mailto:[email protected]>> wrote:
If you have any specific issues let us know, we'll do our best to
make it as
clear as possible for you!
Regards,
Joe Astorino
CCIE #24347 (R&S)
Sr. Support Engineer - IPexpert, Inc.
URL: http://www.IPexpert.com <http://www.ipexpert.com/>
-----Original Message-----
From: Kim Pedersen [mailto:[email protected]
<mailto:[email protected]>]
Sent: Monday, June 08, 2009 2:52 PM
To: Joe Astorino
Cc: 'Tyson Scott'; [email protected]
<mailto:[email protected]>
Subject: Re: [OSL | CCIE_RS] ACL Wildcards
Hi,
Okay, hope when i hit the workbooks something gets clearer on
what exactly
to go through :)
Sincerely,
Kim
Joe Astorino wrote:
> Yeah, you are right there is no "absolute" way like most things in
> this business. 2 lines is just an easy example to show the idea...I
> agree it becomes much more confusing with more. Writing things out
> always helps me to see the big picture clearer. When you write
a line
> for an ACL think through in your head "OK what EXACT range of
> addresses does this permit/deny"
>
>
> Regards,
>
> Joe Astorino
> CCIE #24347 (R&S)
> Sr. Support Engineer - IPexpert, Inc.
> URL: http://www.IPexpert.com <http://www.ipexpert.com/>
>
> -----Original Message-----
> From: Kim Pedersen [mailto:[email protected]
<mailto:[email protected]>]
> Sent: Monday, June 08, 2009 2:46 PM
> To: Joe Astorino
> Cc: 'Tyson Scott'; [email protected]
<mailto:[email protected]>
> Subject: Re: [OSL | CCIE_RS] ACL Wildcards
>
> Hi Joe,
>
> Yeah, i can see that working with 2 lines, but how about more? :)
> and the VOD said it was not an absolute way...
> Phew.. confusing.
>
> Sincerely,
> Kim
>
> Joe Astorino wrote:
>
>> Once you do enough of them, you will find your own patterns and
ways,
>> but if you use simple subtraction and look for the difference
to be a
>> power of 2 that really helps! For instance in the first octet
if you
>> have say 192 and 200 ... 200 - 192 = 8 = 2^3 ...so you know you can
>> match them both with 1 bit in the "8" place.
>>
>>
>> Regards,
>>
>> Joe Astorino
>> CCIE #24347 (R&S)
>> Sr. Support Engineer - IPexpert, Inc.
>> URL: http://www.IPexpert.com <http://www.ipexpert.com/>
>>
>> -----Original Message-----
>> From: [email protected]
<mailto:[email protected]>
>> [mailto:[email protected]
<mailto:[email protected]>] On Behalf Of Kim
>> Pedersen
>> Sent: Monday, June 08, 2009 2:27 PM
>> To: Tyson Scott
>> Cc: [email protected]
<mailto:[email protected]>
>> Subject: Re: [OSL | CCIE_RS] ACL Wildcards
>>
>> Thanks for all of your help...
>>
>> When you guys do it, do you start by writing it all out in
binary,
>> or make an educated guess on what groups together? and it is
best to
>> start with the first octet and going forward, or the last going
backwards?
>>
>> Again, Thanks!
>>
>> Sincerely,
>> Kim Pedersen
>>
>> Tyson Scott wrote:
>>
>>
>>> Yes Correct Kim,
>>>
>>> 194 and 193 can defiantly be matched in one line if all the rest
>>> were the same. In your example none of those could be
combined into
>>> one line without matching additional networks.
>>>
>>> Regards,
>>>
>>> Tyson Scott - CCIE #13513 R&S and Security Technical Instructor -
>>> IPexpert, Inc.
>>>
>>> Telephone: +1.810.326.1444
>>> Cell: +1.248.504.7309
>>> Fax: +1.810.454.0130
>>> Mailto: [email protected] <mailto:[email protected]>
>>>
>>> Join our free online support and peer group communities:
>>> http://www.IPexpert.com/communities
<http://www.ipexpert.com/communities>
>>>
>>> IPexpert - The Global Leader in Self-Study, Classroom-Based, Video
>>> On Demand and Audio Certification Training Tools for the Cisco
CCIE
>>> R&S Lab, CCIE Security Lab, CCIE Service Provider Lab , CCIE Voice
>>> Lab and CCIE Storage Lab Certifications.
>>>
>>>
>>> -----Original Message-----
>>> From: Kim Pedersen [mailto:[email protected]
<mailto:[email protected]>]
>>> Sent: Monday, June 08, 2009 2:02 PM
>>> To: Tyson Scott
>>> Cc: 'Bryan Bartik'; [email protected]
<mailto:[email protected]>
>>> Subject: Re: [OSL | CCIE_RS] ACL Wildcards
>>>
>>> Hi Tyson,
>>>
>>> In my example, those 4 bits are just in the first octet
alone. So
>>> im assuming we really need to treat the entire address, and
not just
>>> by
>>>
>>>
>> octet?
>>
>>
>>> So there's no "set-in-stone" rules to go by, you just sort
of have
>>> to group them, see if that matches and go from there?
>>>
>>> Finally, in my example, if i add the 193 prefix, I would have 6
>>> bits of difference, so the closest i could do in one line is by
>>> matching 64 nets, and this would give an indication on whether i
>>> need to narrow it
>>>
>>>
>> down?
>>
>>
>>> Sincerely,
>>> Kim
>>>
>>> Tyson Scott wrote:
>>>
>>>
>>>
>>>> Kim
>>>>
>>>> When it has a large amount of differences you need to find
>>>> similarities between them to put them together
>>>>
>>>> 194 is 11000010
>>>> 174 is 10101110
>>>>
>>>> This is 4 bit differences so you would have to have 16 entries to
>>>> match
>>>>
>>>>
>>>>
>>> them
>>>
>>>
>>>
>>>> as one line without matching additional subnets
>>>>
>>>> It is important to also note if they say to not match any
>>>> additional networks or if they just say to combine them to as few
>>>> lines without specifying that you can't match additional
networks as
well.
>>>>
>>>> Regards,
>>>>
>>>> Tyson Scott - CCIE #13513 R&S and Security Technical Instructor -
>>>> IPexpert, Inc.
>>>>
>>>> Telephone: +1.810.326.1444
>>>> Cell: +1.248.504.7309
>>>> Fax: +1.810.454.0130
>>>> Mailto: [email protected] <mailto:[email protected]>
>>>>
>>>> Join our free online support and peer group communities:
>>>> http://www.IPexpert.com/communities
<http://www.ipexpert.com/communities>
>>>>
>>>> IPexpert - The Global Leader in Self-Study, Classroom-Based,
Video
>>>> On
>>>>
>>>>
>>>>
>>> Demand
>>>
>>>
>>>
>>>> and Audio Certification Training Tools for the Cisco CCIE R&S
Lab,
>>>> CCIE Security Lab, CCIE Service Provider Lab , CCIE Voice Lab and
>>>> CCIE Storage Lab Certifications.
>>>>
>>>>
>>>> -----Original Message-----
>>>> From: [email protected]
<mailto:[email protected]>
>>>> [mailto:[email protected]
<mailto:[email protected]>] On Behalf Of Kim
>>>> Pedersen
>>>> Sent: Monday, June 08, 2009 11:28 AM
>>>> To: Bryan Bartik
>>>> Cc: [email protected]
<mailto:[email protected]>
>>>> Subject: Re: [OSL | CCIE_RS] ACL Wildcards
>>>>
>>>> Hi Bryan,
>>>>
>>>> I guess I didnt point out the problem (sounds soo serious :) ),
>>>> but what if the question states: "make these into as few
entries as
>>>> possible", and they are soo different that it might not end up in
>>>> one entry (again, with difference in multiple octets).
>>>>
>>>> For example (no logic behind choosing these):
>>>> 194.64.0.96/27 <http://194.64.0.96/27>
>>>> 174.34.87.64/26 <http://174.34.87.64/26>
>>>> 193.23.10.8/30 <http://193.23.10.8/30>
>>>> ...
>>>> Next, imagine 32 addresses just like this :)
>>>>
>>>> How do you go about breaking all of this down?
>>>>
>>>> Sincerely,
>>>> Kim Pedersen
>>>>
>>>> Bryan Bartik wrote:
>>>>
>>>>
>>>>
>>>>
>>>>> Kim, even if there is more than one octet you still can look at
>>>>> the number of bits that are different. Example:
>>>>>
>>>>> 192.168.0.0
>>>>> 192.168.0.1
>>>>> 192.168.1.0
>>>>> 192.168.1.1
>>>>>
>>>>> The above addresses have 2 bits (bit 0 in the 3rd and 4th
octets)
>>>>> that differ and we can combine them in one ACL.
>>>>>
>>>>> 3rd and 4th octets:
>>>>> 0000 0000 | 0000 0000
>>>>> 0000 0000 | 0000 0001
>>>>> 0000 0001 | 0000 0000
>>>>> 0000 0001 | 0000 0001
>>>>>
>>>>> 0000 0000 | 0000 0000 AND
>>>>> 0000 0001 | 0000 0001 XOR
>>>>>
>>>>> 192.168.0.0 0.0.1.1 would be the ACL entry.
>>>>>
>>>>> -hth
>>>>>
>>>>> Bryan Bartik
>>>>> CCIE #23707 (R&S), CCNP
>>>>> Sr. Support Engineer - IPexpert, Inc.
>>>>> URL: http://www.IPexpert.com <http://www.ipexpert.com/>
>>>>>
>>>>> On Mon, Jun 8, 2009 at 7:47 AM, Rodriguez, Jorge
>>>>> <[email protected]
<mailto:[email protected]>
>>>>> <mailto:[email protected]
<mailto:[email protected]>>> wrote:
>>>>>
>>>>> Jeremy this should help you in doing the calculating
wildcard
>>>>> mask
>>>>>
>>>>>
>>>>>
>>>>> http://www.internetworkexpert.com/resources/01700370.htm
>>>>>
>>>>>
>>>>>
>>>>>
>>>>>
>>>>>
>>>>>
>>>>>
>>>
http://blog.internetworkexpert.com/2007/12/26/q-how-do-i-compute-com
>>> p
>>> l
>>> ex-wil
>>>
>>>
>>>
>>>> dcard-masks-for-access-lists/
>>>>
>>>>
>>>>
>>>>
>>>>>
>>>>>
>>>>> Rgds
>>>>>
>>>>> Jorge
>>>>>
>>>>>
>>>>>
>>>>> *From:* [email protected]
<mailto:[email protected]>
>>>>> <mailto:[email protected]
<mailto:[email protected]>>
>>>>> [mailto:[email protected]
<mailto:[email protected]>
>>>>> <mailto:[email protected]
<mailto:[email protected]>>] *On Behalf Of
>>>>> *JEREMY FURR (RIT Student)
>>>>> *Sent:* Friday, June 05, 2009 10:12 AM
>>>>> *To:* [email protected]
<mailto:[email protected]>
>>>>>
>>>>>
>>>>>
>>> <mailto:[email protected]
<mailto:[email protected]>>
>>>
>>>
>>>
>>>>> *Subject:* [OSL | CCIE_RS] ACL Wildcards
>>>>>
>>>>>
>>>>>
>>>>> Does anyone know of a website or book that explains well
how ACL
>>>>> wildcards work? I have been trying to filter out four
blocks from
>>>>> a bunch of route advertisments but just can't get the
three I want
>>>>> through, this is what I have R2 is originating
192.168.2.0/24 <http://192.168.2.0/24>
>>>>> <http://192.168.2.0/24> through 192.168.15.0/24
<http://192.168.15.0/24>
>>>>> <http://192.168.15.0/24> in RIP to R1. I want to only accept
>>>>> blocks 192.168.5.0, 192.168.10.0, 192.168.13.0 and
>>>>> 192.168.14.0
>>>>>
>>>>>
>>>>>
>>>>> If I use acl with 192.168.10.0 0.0.4.0, I will get 10
and 14 but
>>>>> not thirteen. For the 5 network I just use the 192.168.5.0
>>>>> 0.0.0.255.
>>>>>
>>>>>
>>>>>
>>>>> Any thoughts or help would be appreciated.
>>>>>
>>>>>
>>>>>
>>>>> Jeremy Furr
>>>>>
>>>>> [email protected] <mailto:[email protected]>
<mailto:[email protected] <mailto:[email protected]>>
>>>>>
>>>>>
>>>>>
>>>>>
>>>>> --
>>>>>
>>>>>
>>>>>
>>>>>
>>>>>
>>>>
>>>>
>>>>
>>>>
>>>
>>>
>>>
>>
>>
>
>
--
// Freedom Matters
// Follow my progress on: http://kpjungle.wordpress.com
<http://kpjungle.wordpress.com/>
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