do sh traffic-shape
VC Access Target Byte Sustain Excess Interval Increment Adapt
- List Rate Limit bits/int bits/int (ms)
(bytes) Active
128000 1984 7936 7936 62 992
BECN
We have set the rate at 128000. TC=BC/CIR so 7936 /128000=00.62, which is
1/16th of a second. This means we send 128000/16=8000 bits per TC or 1000
bytes. The byte limit is double the sustain (Bc) and excess bits (Be) in bytes,
15872. If we would want to increase the amount of bits sent, we would need to
decrease the time interval. So
traffic-shape rate 128000 15872
would increase the Bc and double it and resulting in a lower time interval
(15872/128000=00.124).
My question is, what does the Byte Limit refer to? Because the byte limit is
(1984*8) 15872, about 16000 bits, not 8000.
The funny thing is, if i divide by the default Tc 1/8th of a second,
128000/8=16000bits ps, then i do get (16000/8) 2000 bytes or, 16000 bits. Which
is the value listed in the above output under byte limit. Am i missing
something here?
And why is it double the Bc and Be?
What does Increment mean? I am trying to figure out the numbers here but i feel
i am making some mistake in here.
Any help would be appreciated.
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