Digging a bit further discovered that its all an XOR operation
so if you want to allow networks 200.0.0.2, 200.0.0.4 and 200.0.0.6
then convert the last octets 2,4 and 6 in binary and perform XOR.
2: 00000010
4: 00000100
6: 00000110
------------------ XOR
00000110 =6
so the mask will be 0.0.0.6
Date: Thu, 26 Jan 2012 20:13:41 +0530
Subject: Re: [OSL | CCIE_RS] wildcard mask volume 1 lab 16
From: [email protected]
To: [email protected]
CC: [email protected]; [email protected]
patrick
why it didnt block 200.0.0.1 , 200.0.0.3 and 200.0.0.5
On Thu, Jan 26, 2012 at 7:42 PM, <[email protected]> wrote:
Yiannis,
200.0.0.0 last octet 00000000
0.0.0.6 last octet 00000110
So the 2 and 4 bits of the last octet are don't care bits resulting in the
options below:
00000000 0
00000010 2
00000100 4
00000110 6
So this part will deny 200.0.0.0, 200.0.0.2, 200.0.0.4 and 200.0.0.6 from
communicating. If you have no additional lines in your access-list nothing will
be communicated because of the implicit deny at the end though.
Kind regards,
Patrick Keja
-----Original Message-----
From: [email protected]
[mailto:[email protected]] On Behalf Of Yiannis -----------
Sent: 26 January 2012 14:51
To: [email protected]
Subject: [OSL | CCIE_RS] wildcard mask volume 1 lab 16
Hi guys,
If you have the following access list
access-list 1 deny 200.0.0.0 0.0.0.6
could you please explain which networks will be allowed/denied and how you
arrive at the result?
Thanks very much
yiannis
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_______________________________________________
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--
With Warmest Regards,
CCIE KID
CCIE#29992 (Security)
_______________________________________________
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