Hi Naren,
 
You exactly got my point! What an amazing explanation!!!
This is not a real network scenario, I was just studying by myself and that 
scenario came to my mind to post the question. I wanted to see if what I 
learned at Cisco Networking Academy works. There is not much to say about it! 
lol
 
Definitely with all of your explanations I understood summarization! 
 
Thanks community!
 
Date: Thu, 25 Jul 2013 20:23:29 -0700
From: [email protected]
Subject: Re: [OSL | CCIE_RS] FW: OSPF Summarization
To: [email protected]; [email protected]

* Correction: in Point number 3 i meant 10.0.35.0/24 & not 10.0.25.0/25 
        From: Narendra Naukwal <[email protected]>
 To: Wilberth E. Lemaître <[email protected]>; 
"[email protected]" <[email protected]> 
 Sent: Friday, 26 July 2013 8:50 AM
 Subject: Re:
 [OSL | CCIE_RS] FW: OSPF Summarization
   
Hi Wilberth,

I would say that the most efficient summarization configuration would depend on 
IP Addressing scheme used else where in your network:

For Example: 
1. You could use 'area 2 range 10.0.32.0 255.255.248.0' on the ABR. 
10.0.32.0/21 would cover range 10.0.32.1 to 10.0.39.255. This one liner summary 
will solve your purpose, however, it will include subnets that do not belong to 
your IP scheme like (10.0.35.0, 10.0.37.0, 10.0.38.0, 10.0.39.0). You can use 
this summary address if these subnets are NOT being used at a different place 
in your network. Also this can be used in case there are more specific routes 
to these
 prefixes.
        --> Routing table
 will have an entry like: {O IA    10.0.32.0/21 [110/11] via 12.0.0.2, 
00:00:11, FastEthernet0/1}

2. You could use 'area 2 range 10.0.32.0 255.255.252.0' on the ABR. This would 
cover range from 10.0.32.1 to 10.0.35.254. This still includes 10.0.35.0/24 
subnet!!  You can use this summary address if prefix 10.0.35.0/24 is NOT
 being used at a different place in your network. Also this can be used in case 
there is
 more specific route to the prefix (10.0.35.0/24)
        --> Routing table will have an entry like: O IA    10.0.32.0/22 
[110/11] via 12.0.0.2, 00:00:18, FastEthernet0/1
                                                                  O IA    
10.0.36.0/24 [110/11] via 12.0.0.2, 00:00:05, FastEthernet0/1

3. If you are using 10.0.25.0/25 network some place else in your network & do 
not want this to be a part of your summary range you could use 'area 2 range 
10.0.32.0 255.255.254.0'. This consists of 10.0.32.1 - 10.0.33.254.
Your routing table after summarization would look like: 
O IA    10.0.34.0/24 [110/11] via 12.0.0.2, 00:00:13, FastEthernet0/1
O IA    10.0.32.0/23 [110/11] via 12.0.0.2, 00:00:04, FastEthernet0/1
O IA    10.0.36.0/24
 [110/11] via 12.0.0.2, 00:02:47, FastEthernet0/1

Hope this helps!Naren

        From: Wilberth E. Lemaître <[email protected]>
 To:
 "[email protected]" <[email protected]> 
 Sent: Friday, 26 July 2013 5:25 AM
 Subject:
 [OSL | CCIE_RS] FW: OSPF Summarization
   
I was able to see the logic, if I use 3 bits the ranges would go like these:
 
10.0.0.0 - 10.0.31.255
10.0.32.0 - 10.0.63.255
10.0.64.0 - 10.0.95.255
 
As we can see, they will all catch in the second range. Correct me if I am 
wrong?

 
From: [email protected]
To: [email protected]
Subject: OSPF Summarization
Date: Thu, 25 Jul 2013 17:27:49 -0600




Hello community,
 
I have a question in regards summarization. 
Let's say I have area 2 configured on a router, the advertised networks are the 
following:
 
router ospf xxx

 network 10.0.32.1 0.0.0.0 area 2
 network 10.0.33.1 0.0.0.0 area 2

 network 10.0.34.1 0.0.0.0 area 2
 network 10.0.36.1 0.0.0.0 area 2
 network 192.168.0.2 0.0.0.0 area 0
 
I want to summarize area 2, the mechanism I use for summarization is the 
following and correct me if I am wrong. I look for the octet where the decimal 
number changes, or where the bits are not equal. As we can see this happens on 
the 3rd octet and I start using increments with each octet value:
 
128 64 32 16 8 4 2 1 
 
I wonder myself which increment or which number would catch all of those into 
one advertisement counting from zero, in other words, how many binary digits I 
have to convert to 1 in order to do the summarization. 
Based on this scenario, 32 would catch less than what we need, 64 would be the 
perfect one, and I will need to convert only 2 bits (the first 2 bits) and  my 
subnet mask would look like 11111111.11111111.11000000.00000000 and the network 
range would go like this:
 
10.0.0.0 -
 10.0.63.255
10.0.64.0- 10.0.127.255
 
As we can see, if I use a subnet mask of 18, I will be including ranges that 
are NOT necessary.
 
What would be the efficient summarization in order to accomplish this scenario? 
Please explain ;)
 
Best regards,
Wilberth 
 
 
 

 
                                                      
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