Aha, so I have re-invented the wheel! But I never made sense of why f' is
negative--this is beautiful! Just to make sure: you are saying that the real
part of the anomalous scattering goes negative because those photons are
sneaking out of the diffraction pattern through absorption-->fluorescence?
Jacob
*******************************************
Jacob Pearson Keller
Northwestern University
Medical Scientist Training Program
Dallos Laboratory
F. Searle 1-240
2240 Campus Drive
Evanston IL 60208
lab: 847.491.2438
cel: 773.608.9185
email: j-kell...@northwestern.edu
*******************************************
----- Original Message -----
From: "Ethan Merritt" <merr...@u.washington.edu>
To: "Jacob Keller" <j-kell...@md.northwestern.edu>; <CCP4BB@jiscmail.ac.uk>
Sent: Friday, April 24, 2009 1:40 PM
Subject: Re: [ccp4bb] Reason for Neglected X-ray Fluorescence
On Friday 24 April 2009 11:28:16 Jacob Keller wrote:
Dear Dr. Holton and CCP4BBers,
Are you saying that a resonant event is always accompanied by a
fluorescence
event? If that were true, wouldn't the resonant event end up manifesting
as
*negative* scattering component from the resonant atom, due to the
elimination of an otherwise-scattered photon, this making the resonant
atom
"darker" than would be expected?
Yes.
That is why the real component of the scattering factor, f', is negative.
--
Ethan A Merritt
Biomolecular Structure Center
University of Washington, Seattle 98195-7742
