PAK=0 is GOOD - i.e. there are no clashes between symmetry equivalent
molecules.
So I think you have solved your structure.
Eleanor

On 15 September 2017 at 07:20, rohit kumar <rohit...@gmail.com> wrote:

> Dear all,
>
> During MR using PHASER with a 1.8 A data, I found that the PAK=0 but all
> the other values are looking fine.
>
> When I run REFMAC5 the R/Rfree values are 25/30 (without water) and 21/26
> (after adding water).
>
> Just want to know whether my solution is correct or not. if not please let
> me know what strategies I can use to get correct solution.
> As I have tried all the combination in PHASER.
>
> Here I am attaching the result of PHASER .
>
>
>
> [image: Inline image 3]
>
>
> Thank you in advance
>
> --
> WITH REGARDS
> Dr. Rohit Kumar Singh
>
>

Reply via email to