Well - you haven't said what the sequence identity between model and your
protein is, nor if you have a non-crystallographic translation.

With low homology that R factor drop is acceptable and rebuilding can fix
it, However if there is high homology you might expect better.

But this sort of conjecture is pretty pointless - check in all orthorhombic
 space groups as Mark suggests.

Eleanor

On 19 September 2017 at 15:16, Mark J van Raaij <mjvanra...@cnb.csic.es>
wrote:

> With Rs of 43/48% I don't think you can be sure that your spacegroup is
> right.
> You should always try all the spacegroup possibilities until you get a
> solution you are sure is right, i.e. that refines to Rs of around 35% or
> preferably even lower.
> More so in the case of screw axes, so try P222, P2122, P2212, P2221,
> P21212, P21221, P22121 and P212121. Phaser can do this automatically for
> you by clicking the right box.
> If necessary, then try lower symmetry like P21 and perhaps P1.
> Programs like Xanuda can help.
>
>
> Mark J van Raaij
> Dpto de Estructura de Macromoleculas
> Centro Nacional de Biotecnologia - CSIC
> calle Darwin 3
> E-28049 Madrid, Spain
> tel. (+34) 91 585 4616 <+34%20915%2085%2046%2016>
> http://wwwuser.cnb.csic.es/~mjvanraaij
> Editor of Acta Crystallographica F, Structural Biology Communications
> http://journals.iucr.org/f/
>
> On 19 Sep 2017, at 16:01, Satvik Kumar <kumarsatvi...@gmail.com> wrote:
>
> Hello,
>
> Thanks everyone for your explanations.
>
> I have pasted the pointless output to provide more information.
>
> Best Solution:                                  space group P 21 21 21
>
> Laue group probability:                   0.959
>
> Systematic absence probability:     0.818
>
> Total probability:                             0.785
>
> Space group confidence:                0.751
>
> Laue group confidence                   0.951
>
>
> Unit cell:   82.10 100.51 157.11     90.00  90.00  90.00
>
> Also based on L-test, pointless says data does not suggest twinning.
>
> Yes, the R values go down when I refine in both cases. After 20 rounds of 
> restrained refinement using the coordinates generated by monomer as search 
> model, the Rwork and Rfree are 0.43 and 0.48
>
> respectively. Refinement using the coordinates generated by using dimer as
> search model also results in similar R values. I have attached the plots to
> show that the R values indeed reduce in both cases.
>
> Is my space group correct? Do I need to reexamine the space group even
> though the probability is high?
>
> If my space group is indeed correct, how do I decide whether to go ahead
> with the results generated by the monomer search model or the dimer?
>
> Please share your thoughts.
>
>
> Thanks,
> Satvik
>
> On Mon, Sep 18, 2017 at 7:36 PM, Eleanor Dodson <eleanor.dod...@york.ac.uk
> > wrote:
>
>> You need to provide a bit more information.
>>
>> First of all about the data processing..
>>
>> Is the space group correct?
>> ways of being misled are:
>> Non-crystallographic translations with a shift of ~0.5 along an axis -
>> say a.  This will generate absences in the odd h 0 0 reflections and can
>> make the space group appear to be P 21 21 21 whilst it is really P 2 21 21..
>>
>> Perfect twinning can have the same effect. In an orthorhombix space group
>> this can usually only occur if two axes have approximately the same length,
>> but the data processing stats can indicate if that is the case.
>>
>> Then - re PHASER. The packing rejection criteria may be set too severely
>> - that seems the case for your solution.
>>
>> Best check on any MR solution is: does it refine - give it 20 cycles of
>> mindless refinement and see if the R and FreeR go down.
>>
>> Then look at the maps and see if there are obvious corrections to be
>> made..
>>
>> Eleanor
>>
>> On 18 September 2017 at 14:59, Satvik Kumar <kumarsatvi...@gmail.com>
>> wrote:
>>
>>> Dear Crystallographers,
>>>
>>> I am trying to solve a structure in the space group P212121. Based on
>>> Matthews coefficient, there are 4 molecules in the asymmetric unit.
>>>
>>> Based on my limited reading about using of Phaser, I understand that a
>>> single chain should be used as search model even though many copies are
>>> present in asymmetric unit. Am I correct?
>>>
>>> So when I use a single chain as search model and ask Phaser to search
>>> for 4 molecules, Phaser identifies a single solution with a warning "The
>>> top solution from a TF rescoring did not pack" and a warning "Search
>>> request requires more scattering than defined in composition. Composition
>>> increased to accommodate search components". But the final values reported 
>>> "PAK=2
>>> LLG=1065 TFZ==22.6" indicate that phaser has solved the problem.
>>>
>>> Can anyone please explain the meaning of the warning.
>>>
>>> When I inspect the arrangement of the chains (attachment), I observe
>>> minimal contact between the chains and a large cavity in the center. Can a
>>> crystal form this way?
>>>
>>> I have also tried using the dimer as search model and asking phaser to
>>> search for 2 molecules. Even in this case, Phaser finds a single solution
>>> but the warning and the advisory still appear as before. The numbers
>>> reported reduce a bit to "PAK=1 LLG=722 TFZ==29.2".
>>>
>>> Please help me in understanding these results.
>>>
>>> Thanks,
>>> Satvik
>>>
>>>
>>>
>>
> <Monomer_searchmodel.pdf><Dimer_searchmodel.pdf>
>
>
>

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